Spiral Knights - Big Number Thread (Try to express the biggest number possible!)

Big Number Thread (Try to express the biggest number possible!)

42 replies [Last post]

Sun, 10/05/2014 - 16:49

Deleted-Knight

This game is kind of like king of the hill, except the "king" is whoever holds the record for biggest number defined.

To keep things under control there are some rules
Your number...
1. Must be a positive integer (FYI, anything with infinite digits is not an integer)
2. Must have a fixed value (eg. "one more than the biggest number anyone else posts" is not allowed*)
3. Must be expressed in fewer than 200 characters (eg. no spamming digits)
4. Cannot use any numbers already assigned a special name by mathematics (eg. "Graham's number" cannot be used when defining your number)

Other than that, you are free to write whatever you want to describe your number.

*You can reference anything you want that doesn't break rule #4, but it has be something that won't change as the game progresses. For example, "the diameter of the earth in millimeters" is okay, since someone can look up the diameter of the earth and calculate that number regardless what is posted afterwards.
Please provide a link to back up your references. Like if you say "number of galaxies in the universe", link to a page with an estimate of that number.

Sun, 10/05/2014 - 16:52

Deleted-Knight

I'll start off easy

9999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999

^That is 199 characters worth of 9s

Sun, 10/05/2014 - 17:04

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

I win

Oh fine, infinity.

Googolplex to the Googolplex power is my number

Sun, 10/05/2014 - 17:02

Drax-Infinire

Yup.

Volume of the sun and earth combined in Angstroms^3, all to the power of 100.

Sun, 10/05/2014 - 17:13

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

@Ergir all the strings (The string theory kind) in all of spacetime to the power of a googleplex

Sun, 10/05/2014 - 17:30

Deleted-Knight

Ugh didn't see that loophole

Okay, you can't just reference stuff. You need to give a link that shows someone did the math for it.

Edit:
Googol is apparently a special mathematical term coined by somebody. So it's not allowed. However, Wikipedia does offer "ten duotrigintillion" as a possible replacement.

Ergir is currently in the lead with a number that's approximately 10^(5700)

Sun, 10/05/2014 - 17:57

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

Oh fine, the number of atoms in the universe to the power of ten duotrigintillion

Sun, 10/05/2014 - 18:14

Sonosuke

*insert amount of 9s*

999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999998999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999998999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999 to the power of 999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999998999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999998999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999

Sun, 10/05/2014 - 18:22

Brother-Zeke

Number of hydrogen atoms in 1.00794 grams of hydrogen to the power of the number of hydrogen atoms in 1.00794 grams of hydrogen.
All multiplied by ten & ten & ten then put to the power of the number of hydrogen atoms in 1.00794 grams of hydrogen.

That is two hundred characters not counting spaces.

Sun, 10/05/2014 - 20:25

Drax-Infinire

I AM EVAL ARENT I

Volume of the sun^999 duotrigintillion and earth^999 duotrigintillion combined (all so far to the power of 999 duotrigintillion) in Angstroms^3, all to the power of 9999 duotrigintillion to the power of 9999 duotrigintillion to the power of 9999 duotrigintillion. #rekt!

EDIT: @Crazee-Pi-Forums The radon is decreasing in the universe. Your number is jelly.
DOUBLE EDIT: Maybe it's just turning into something else. You win that one.

Mon, 10/06/2014 - 13:27

#10

Deleted-Knight

Please include links to references guys >.<

I can't find everything on Wolfram Alpha ya know.
Ergir's latest post holds the lead, which is estimated to be about 10^(5.7 * 10^415).

@Sonosuke: Read rule #3

@Ergir: The earth is so small compared to the sun it doesn't make a difference if you add it in or not, just saying. Also, when you say "to the power of" I can't tell where the parentheses go, so I just go from left to right.

@Everyone else: Have you noticed I've been writing the records so far with fewer than 20 characters? That means you guys are being horribly inefficient with your resources! I just compressed 100+ characters into 20.

Mon, 10/06/2014 - 13:54

#11

Brother-Zeke

Take Two

I didn't want to do this but I suppose it'll work.

n=9999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999

(((((((((((((((((((((((((n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n

200 characters not counting the intro+this sentence+spaces

Also no rule on entering twice. :P

I have no clue if that will be bigger.

Mon, 10/06/2014 - 15:46

#12

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

10^(9 x 10^999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999)

I'll take my prize now.

Mon, 10/06/2014 - 17:01

#13

Deleted-Knight

Alright, now the party's actually started, kinda

Zeke's number:
n = 10^97 - 1, so I'm going to assume it's 10^97
The power chain simplifies to n^(n^25) which makes 10^(97 * (10^(97*25)) = 10^(9.7 * 10^2426)

Pi's number:
Assume those 187 9s are actually 10^187 (which is rounding up) making the number 10^(9 * 10^(10^187))

Pi is the new King. Thanks for the catch Pi ;)

Mon, 10/06/2014 - 16:57

#14

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

No, that's not right. It's 10^999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999, not 187, technically meaning I'm the king

Mon, 10/06/2014 - 17:12

#15

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^(10^99)))))))))))))))))))))))))))))))))))))))

I think that's greater, I might have not put the correct amount of parentheses at the end though

Tue, 10/07/2014 - 04:08

#16

Green-Neko

Huh

Just start from one and continue to count non-stop from there. Add the circumference (in picometers) of the sun, the moon, the earth, and every other heavenly bodies in the milky way. Then add everything you guys added above and will add below. Now give me some sugar. And maybe the crown.

Tue, 10/07/2014 - 14:15

#17

Brother-Zeke

I am just simply... adapting Pi's ideas.

99^99999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999

And/or

99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^99)))))))))))))))))))))))))))))))))))))))

The first being 200 characters and the second 200.

Tue, 10/07/2014 - 18:44

#18

Deleted-Knight

Zeke is currently winning

Record so far (by Brother Zeke):
99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^(99^99)))))))))))))))))))))))))))))))))))))))

I think I can still compress it, but I won't give you guys any more ideas now :P

@Green-Neko
Read the rules carefully.

Tue, 10/07/2014 - 19:04

#19

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

One more then post 17's number (Technically has a fixed value, unless Zeke does an edit)

But seriously, 9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(99^99)))))))))))))))))))))))))))))))))))))))))))))))) or 9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^999)))))))))))))))))))))))))))))))))))))))))))))))), whichever is higher

Tue, 10/07/2014 - 21:35

#20

Cryptian

Your pants are very crunchy...

Assume † = 1 duotrigintillion

†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(99^99))))))))))))))))))))))))))))))))))))))))))))))))

Do I win?

Tue, 10/07/2014 - 22:25

#21

Deleted-Knight

Crazee-Pi is new King

Record value is:
9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^(9^999))))))))))))))))))))))))))))))))))))))))))))))))

No estimate available, I used analysis to determine it is more "dense" than Zeke's (which is why you have a strict character count).
To give you guys an idea of how large the records are at the moment: 9^(9^(9^9)) is over 360 million digits long in base 10.

@Cryptian
You have just unlocked a new strategy! Unfortunately your definition of † made it exceed 200 characters, so I cannot count your post.

@Pi, regarding Neko
He said "you guys add" which means everything that will be added, not just one post. Even if it were one post, Zeke could edit, causing confusion.

Wed, 10/08/2014 - 16:21

#22

Cryptian

Your pants are very crunchy...

Mehhh

Assume † = 1 duotrigintillion

†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†^(†*†)))))))))))))))))))))))))))))))))))))))))))

How bout nao?

Wed, 10/08/2014 - 16:54

#23

Deleted-Knight

Pi is still the King

Cryptian, you are making life difficult for me! But it's fine since I like puzzles :P

Your expression can be rewritten as: 10^(10^(2+(10^(2+(10^... , which would clearly be bigger than Pi's number if you repeated it the same number of times. Unfortunately you had to chop some off to get it to a respectable character count. Chopping even little bit off the end of a power tower makes many magnitudes of difference. I think Pi's number is still bigger.

If someone can demonstrate otherwise, I will give the crown to you.

Wed, 10/08/2014 - 17:47

#24

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

EDIT:

Wed, 10/08/2014 - 17:40

#25

Deleted-Knight

@Crazee-Pi 1. I was going to

@Crazee-Pi
1. I was going to leave out "assume" since it doesn't really give more information.
2. I can't tell the order of ops of your x definition if you don't put parentheses.
3. You're still the current king, so idk why you want to break your own record. The timer is for 2 days, so you don't want to reset it by breaking your own record.

Thu, 10/09/2014 - 14:29

#26

Brother-Zeke

Hmmm....

N=duotrigintillion
Z=My number
Given the following geometric sequence where the first term=N^N, find the Nth term, where the Nth term is equal to Z.

@Deleted-Knight
"I don't know what the prize is going to be yet"
"I will give the crown to you"

That seems a bit cheap.

Also my wording is probably crap and turns out to be nothing.

Thu, 10/09/2014 - 16:36

#27

Deleted-Knight

Haha, very funny Zeke

The prize is not the hypothetical crown. The "crown" is just another way to say you are the current Big Number King. I haven't really dug through my main account, but I will choose something that is somewhat valuable. Worst case scenario I give you 6k crowns. If I were richer, I would have a bigger prize, but I mostly spend my SK days playing LD instead of making money.

Also you didn't give the R value for your geometric series. Even if you did, it's probably smaller since the value would be (N^N)*R^N, which is much smaller than N^(N^(N^N)) unless you make r something ridiculous.

@Everybody:
Crazee-Pi is set to win the contest in less than 3 hours!

Thu, 10/09/2014 - 16:53

#28

Brother-Zeke

All right, let me actually fix it. I think. Maybe. I hope it's formatted correctly. You can understand what's on top of the sigma.

N=duotrigintillion
Z=My number

((((((((((((((n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)
Z=Σ ((((((((((((((((((((((((((((n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)
. n=1

200 characters. That period doesn't count, just to space the n=1 out a bit.

Thu, 10/09/2014 - 19:49

#29

Deleted-Knight

GG. Crazee-Pi wins.

@Zeke
The sigma you wrote is for cumulative summation. I will assume it's a cumulative product symbol (which is actually pi) to give you the benefit of doubt. Unfortunately you wrote ((((((((((((((n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n)^n). Notice where the parentheses are. That's just n^(13n)
Same thing with the term inside your summation.
So your number is not even close to the record... Sorry.

@Crazee-Pi
Give me an IGN to send your prize to. You've unlocked a new title: Big Numba King

Thu, 10/09/2014 - 20:04

#30

Deleted-Knight

Here's something to chew on

Define series A:
A[0] = 9!
A[n+1] = A[n]^A[n]
Define series B:
B[0] = 9!
B[n+1] = A[B[n]]
Define series C:
C[0] = 9!
C[n+1] = B[C[n]]

My number = Sum of C up to the (9!)th-term

^178 characters, how big is my number?

Thu, 10/09/2014 - 20:07

#31

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

IGN: Pipipipipi

Thu, 10/09/2014 - 21:31

#32

Deleted-Knight

@Pi

I sent out the prize, if you didn't get it, let me know.

Fri, 10/10/2014 - 08:14

#33

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

Got it

For those who are curious

Fri, 10/10/2014 - 08:31

#34

Straight-Line

I know the "contest" is over but for the next one (if there is a next one):

3. Must be expressed in fewer than 200 characters (eg. no spamming digits)
@Sonosuke: Read rule #3

Deleted-Knight, read you own rule 3, I believe it says no spamming numbers

Fri, 10/10/2014 - 09:13

#35

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

They mean you can't just put 9 over and over 9001 times, but you can spam 9 200 times

Fri, 10/10/2014 - 11:40

#36

Doctorspacebar

Hmm. I like this road. It seems to have a... food motif.

Let a = the number of electrons in the known universe.

Now a^a^a = b, b^b^b = c, and so on for each increase in hex value required to receive the character until z. Now let z^z^z^z^z = A, A^A^A^A^A = B, B^B^B^B^B = C, and so on for each increase in hex value until Z.

Let Z^Z^Z^Z^Z^Z^Z=α. Let α^α^α^α^α^α^α^α = β. Let β^β^β^β^β^β^β^β^β = γ. Continue the pattern down the lowercase greek alphabet until you define ω.

Now let ω^ψ^χ^φ^...^β^α^Z^Y^...^C^B^A^z^y^...^c^b^a = Α (Greek Uppercase Alpha). Now let Β (Greek Uppercase Beta) = Α (Greek Uppercase Alpha) ^ Α (Greek Uppercase Alpha) ^ ω^ω^ψ^ψ^χ^χ^φ^φ^...^β^β^α^α^Z^Z^Y^Y^...^C^C^B^B^A^A^z^z^y^y^...^c^c^b^b^a^a. Continue this pattern down the Uppercase Greek Alphabet to define Ω.

Ω is a freaking huge number.

EDIT: Oh, crap. This has so many characters that it breaks the rules, doesn't it?

Fri, 10/10/2014 - 11:44

#37

Straight-Line

Contest is done. Gg, graveyard this now.

Fri, 10/10/2014 - 13:13

#38

Deleted-Knight

Why the hate Straight-Line?

The contest is over, but if people want to continue for fun, why not? It's in gremlin chatter so it's not inappropriate.

Fri, 10/10/2014 - 13:59

#39

Straight-Line

I have a strong habit of hating on topics. You are free to reach out of the inernet and unplug my mouse and keyboard if you wish.

Sun, 10/26/2014 - 08:16

#40

Tender-Footmender

8 turned sideways is the largest number.

Wed, 10/29/2014 - 23:35

#41

Abelisk

3.141592653589793238462643383279502884197169399375105
82097494459230781640628620899862803482534211706798
21480865132823066470938446095505822317253594081284
8111745028410270193852110555964462294895493038196

Wed, 10/29/2014 - 23:39

#42

Crazee-Pi-Forum

Nothing is scary when you add Tetris music!

TEN BILLIONS! I WINDAS SADSAODMASOFASDMA YAY!

WE NEED DIS CONTEST IN DA OPPOSITE WAY! SMELLYEST IN 200 CHARACTERS NOT FROM BOOKS

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Big Number Thread (Try to express the biggest number possible!)