Is it directly multiplicative (2 ppl = 2x hp)? Or is there some other formula used? I just beat Vanaduke solo for the first time and it just occurred to me that I didn't know this one fact.
How exactly does monster hp scale with party size?
Sat, 02/18/2012 - 20:47
Sat, 02/18/2012 - 21:34
#2
Theory
I think it scales like this. (Though I don't have any factual backup on this)
1 person: 1x HP
2 persons: 1.5x HP
3 persons: 2x HP
4 persons: 2.5x HP
Maybe someone else has some actual knowledge on this subject.
Sun, 02/19/2012 - 00:33
#3
--
Well, in the FSC, using a DA w/ max heat and DMG bonus, it takes me 2 hits solo, 3 for 2 & 3, and 4 for a full party to kill a red rover (that is, if I always use and connect with the entire combo; it takes a few more whacks if I gotta just spam the first attack).
Best way to test this is to have some guy with a proto sword count how much damage it takes him to kill a monster in each party configuration. You could use a more powerful weapon, but then the margin of error is greater. I lack the patience and sufficient amount of insanity to do this.
Sun, 02/19/2012 - 13:27
#4
I did some testing on this a
I did some testing on this a while back. Each additional party member increases monster HP by 33% of the base value, at least for Depth 1. I'm pretty sure this rule applies to the Clockworks in general, though.
Depth 1 Gun Puppy
1 person: 40 HP
2 people: 53 HP
3 people: 66 HP
4 people: 80 HP
Sun, 02/19/2012 - 14:37
#5
I see
Thanks Otaia, that's really helpful. This info really should be in the wiki.
Congrats on the solo! And I don't know the exact scaling, but it isn't a direct multiplier. It scales more from 3 to 4 members I believe, than from 2 to 3, but it is less than a direct multiplier.